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Daily question--This is a question asked of TUTORING.COM by a student taking Algebra II:

Question: Find the y-intercept of f(x) = -3(x-2)^2 + 4

Answer by TUTORING.COM:

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Thus the y-intercept of y = f(x) is the value of y when x = 0, which is: y-intercept = f(0)

For f(x)=-3(x-2)^2+4 , the y-intercept is: y-intercept = f(0) = -3(0-2)^2 + 4 = -3(-2)^2 + 4 = -3(4) + 4 = -12 + 4 = -8

So the y-intercept for the function f(x)= -3(x-2)^2 + 4 occurs at y = -8 , or at the (x,y) point (0, -8)

The graph of the function y = -3(x-2)^2 + 4 (which is a PARABOLA pointing DOWN) is

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